If 2083 joules are used to melt 5.26 grams of aluminum, what is the heat of fusion of aluminum?

Hf = 396.007 J/g

Explanation:

Q = 2083J

Mass = 5.26g

Q = m*Hf

Q = energy

M = mass of aluminium

Hf = heat of fusion

Q = mHf

Hf = Q / m

Hf = 2083 / 5.26

Hf = 396.007 J/g

The heat of fusion of aluminium is 396.07 J/g

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

the answers would be

the first one and the second one