Asolution is made by dissolving 0.0150 mol of hf in enough water to make 1.00 l of solution. at 26 °c, the osmotic pressure of the solution is 0.449 atm. what is the percent ionization of this acid?

As the osmotic pressure = (molarity)(gas constant)(temp)
 so we can use the given information to find the molarity of the solution so  that would give us that osmotic pressure...
so... 0.449atm = (Molarity)(0.08206 Latm/molK)(299K)
  so the Molarity = 0.0183
 and the total particles in the solution will be concluded by
 this molarity - the given molarity
so... by putting values
0.0183-0.0150 = 0.0030 M
 now we then put this value over the value given molarity which will give us the  percent ionization.
 that is
0.0030M/0.0150M
 = 0.200
 = 20.0%
so the 20.0% is the percent ionozation of this acid
hope it helps

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !