(6 pts.) How many liters of 2.50% m/v NaCl solution will be needed in order to contain 858 g of
NaCl? Show calculation with conversion factors.

34.32 liters

Explanation:

34.32 liters of 2.5% m/v NaCl solution will be needed in order to contain 858 g of NaCl.

2.5% m/v NaCl solution contains 2.5 g of NaCl in 100 mL of solution. It thus means that 100 mL has 2.5 g of NaCl.

If 100 mL solution contains 2.5 g NaCl, then, how many mL will contain 858 g?

= 100 x 858/2.5 = 34, 320 mL

Now, convert 34,320 mL to liters

1 mL = 0.001 Liters

34,320 mL = 34,320 x 0.001 L

   = 34.32 liters.

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

if you need further assistance, let me know: )

~ trueboss72