I am doing a gizmo and need help badly, this is what is on the worksheet. Can someone please help me, I am struggling a lot. Thank you.

6. Practice: Solve each of the following problems using dimensional analysis (or another method). Show your work. (Use a periodic table to look up the necessary atomic masses.)
A. 75 g KMnO4 = molecules KMnO4
B. 7.23 × 10 24Al atoms = grams Al
C. 9.23 × 10 23Au atoms = moles Au
D. 125 g H3PO4 = molecules H3PO4
E. 0.75 moles CO2 = total atoms

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

answeridentity;