Question 8

in a titration, 25.0 ml of 0.500 m khp is titrated to the equivalence point with naoh. the final solution volume is 48.5 ml. what is the value of m2 for the reaction?

0.256 m

0.532 m

0.970 m

0.500 m

Answer : The value of (concentration of NaOH) for the reaction will be, 0.532 M

Explanation :

Using neutralization law,

where,

= basicity of an acid (KHP) = 1

= acidity of a base (NaOH)  = 1

= concentration of = 0.500 M

= concentration of NaOH = ?

= volume of = 25 ml

= volume of NaOH = 48.5 - 25 = 23.5 ml

Now put all the given values in the above law, we get the concentration of the .

Therefore, the value of (concentration of NaOH) for the reaction will be, 0.532 M

2b2t

explanation:

2b2t

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa