When 61.6 g of alanine (C, H,NO,) are dissolved in 1150. g of a certain mystery liquid X, the freezing point of the solution is 2.9 °C lower than the freezing point of pure X. On the other hand, when 61.6 g of ammonium chloride (NH, CI) are dissolved in the same mass of X, the freezing point of the solution is 7.3 °C lower than the freezing point of pure X Calculate the van't Hoff factor for ammonium chloride in X Be sure your answer has a unit symbol, it necessary, and is rounded to the correct number of significant digits.

1.5

Explanation:

To solve this problem we use the freezing-point depression equation:

ΔT = Kf * m * i

Where ΔT is the difference in temperature, Kf is the cryoscopic constant of the solvent, m is the molality, and i is the van't Hoff factor.

For the case of alanine (C₃H₇NO₂, MW = 89 g/mol):

ΔT = 2.9 °C

m = mol alanine / kg X

1150 g X ⇒ 1150 / 1000 = 1.15 kg

61.6 g alanine ÷ 89g/mol = 0.692 mol

m = 0.692 mol / 1.15 kg = 0.601 mi = 1

So now we calculate the cryoscopic constant of the liquid X:

ΔT = Kf * m * i2.9 °C = Kf * 0.601 m * 1Kf = 4.82 °C / m

Now we use the same formula for the case of ammonium chloride (NH₄Cl,  MW = 53.49 g/mol)

ΔT = 7.3 °C

61.6 g NH₄Cl ÷ 53.49 g/mol = 1.15 mol

m = 1.15 mol / 1.15 kg = 1 m

And calculate i :

7.3 °C = 4.82 °C/m * 1m * ii = 1.5

The van't Hoff factor is unitless.

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Mass is the amount of matter in an object.  weight is the measurement of the pull of gravity on an object.  say for example, you travel to the moon which has a different gravitational field compared to the gravitational field of earth. (gravitational fields: earth = 1, moon = 0.165)  now when you are on the moon, the pull of gravity on you is different than on the earth. and as weight is the measurement of the pull of gravity on an object, that means yes, your weight can and will change on the moon.  however, on the moon, on earth or even on jupiter, the amount of mass inside of you remains the same. meaning your physical mass remains constant.  in conclusion it is possible for your weight to change as your mass remains constant.