For each chemical reaction, fill in the exponents in the formula for Ks
BaCro (s) + Ba?- (aq) + Cro?- (aq)
K., =[Ba?"1" [CRO-
Mg(OH)2 + Mg²+(aq) + 20H (aq)
Ks = [Mg²+1"[OH]
SIF (S)
Sr- (aq) + 2F"(aq)
Cuz (PO4)2(s) + 3Cu?- (aq) + 2PO, 2 (aq)
Kg = [Cu²+ ][PO, 1
K., = [Sr2-1 [F-1

The answer to your question is given below

Explanation:

BaCrO4(s) <=> Ba^2+(aq) + CrO4^2-(aq)

Ksp = [Ba^2+]^A [CrO4^2-]^B

From the equation above,

Ba^2+ and CrO4^2- has 1 coefficient each. Therefore, the Ksp is given as:

Ksp = [Ba^2+] [CrO4^2-]

A = 1

B = 1

Mg(OH)2 <=> Mg^2+(aq) + 2OH^-(aq)

Ksp = [Mg^2+]^D [OH^-]^E

From the above equation,

Mg^2+ has a coefficient of 1

OH^- has a coefficient of 2

Therefore, the Ksp can be written as:

Ksp = [Mg^2+] [OH^-]^2

D = 1

E = 2

SrF2(s) <=> Sr^2+(aq) + 2F^-(aq)

Ksp = [Sr^2+]^C [F^-]^D

From the equation above,

Sr^2+ has a coefficient of 1.

F^- has a coefficient of 2.

Ksp = [Sr^2+] [F^-]^2

C = 1

D = 2

Cu3(PO4)2(s) <=> 3Cu^2+(aq) + 2PO4^3-(aq)

Ksp = [Cu^2+]^F [PO4^3-]^G

From the equation above,

Cu^2+ has a coefficient of 3

PO4^3- has a coefficient of 2

Ksp = [Cu^2+]^3 [PO4^3-]^2

F = 3

G = 2

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error