A chemistry student adds a quantity of an unknown solid compound X to 5.00 L of distilled water at 15 degrees Celsius. After 10 minutes of stirring, only a little X has dissolved. The student then drains off the solution and evaporates the water under vacuum. A precipitate is left behind. The student washes, dries, and weighs the precipitate. It weighs 0.17 kg. Can you calculate the solubility of X in water at 15 degrees Celsius?

34 g/L

Explanation:

From the question, only 0.17Kg of the solvent dissolved in the water.

Solubility is defined as the amount of solute that dissolves in 1L of solvent.

But 0.17Kg is the same as 170g of solute

Hence 170g of solute dissolved in 5L of solvent

x g of solute will dissolve in 1L of solvent

x= 170/5 = 34 g/L

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explanation:  

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