Chemistry, 06.05.2020 07:23 MarMarMar07

A student needs to dilute a 0.31 M Pb(NO3)2 solution to make 83.0 mL of 0.19 M Pb(NO3)2 . Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.31 M Pb(NO3)2 solution that is needed.

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Answer from: ryleigh1780

Answer : The volume, in milliliters, of the 0.31 M Pb(NO_3)_2 solution that needed is, 50.9 mL

Explanation :

Formula used :

M_1V_1=M_2V_2

where,

$M_1\text{ and }V_1$ are the initial molarity and volume of dilute Pb(NO_3)_2 .

$M_2\text{ and }V_2$ are the final molarity and volume of Pb(NO_3)_2 .

We are given:

$M_1=0.31M\\V_1=?\\M_2=0.19M\\V_2=83.0mL$

Putting values in above equation, we get:

$0.31M\times V_1=0.19M\times 83.0mL\\\\V_1=50.9mL$

Hence, the volume, in milliliters, of the 0.31 M Pb(NO_3)_2 solution that needed is, 50.9 mL

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A student needs to dilute a 0.31 M Pb(NO3)2 solution to make 83.0 mL of 0.19 M Pb(NO3)2 . Set up the...

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