Suppose a 250.mL flask is filled with 0.70mol of H2 and 1.6mol of HCl. The following reaction becomes possible:

H2 (g) + Cl2 (g) <---> 2HCl (g)

The equilibrium constant K for this reaction is 0.262 at the temperature of the flask. Calculate the equilibrium molarity of HCl. Round your answer to two decimal places.

6.97 M

Explanation:

The reaction that takes place is

H₂(g) + Cl₂(g) ↔ 2HCl (g)

With a equilibrium constant ke =   = 0.262

The original concentrations for each species are:

250 mL ⇒ 250 / 1000 = 0.25 L

The ICE table thus is:

                      H₂(g) + Cl₂(g) ↔ 2HCl (g)

Initial                 2.8      0           6.4

Change            -x          -x             +2x

Equilibium        2.8-x      0-x        6.4 + 2x

So the equilibrium molarity of HCl is 6.4 + 2*0.285 = 6.97 M

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.