2 Fe(s) + 6 HCl(aq) →2 FeCl3(aq) + 3 H2(g) ΔHa
Fe2O3(s) + 6 HCl(aq) → 2 FeCI3(aq) + 3 H2O(l) ΔHb
2 H2(g) + O2(g) → 2 H2O(l) ΔHc
Show how these equations must be summed together according to Hess’s Law to determine ΔH for the combustion of iron (target equation shown below). Also show clearly how the ΔH values of each of the three reactions must be manipulated to determine the enthalpy of combustion of iron.
4 Fe(s) + 3 O2(g) → 2 Fe2O3(s) ΔH = ?

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >