Calculate the % composition of nitrogen (N) in ammonium nitrate, NH4NO3.

35.00%

Explanation:

In order to find the percent composition, we need to find out the mass of nitrogen in the compound divided by the total mass of the compound.

According to the periodic table, the molar mass of nitrogen (N) is 14.01; for hydrogen (H) it's 1.01; and for oxygen (O), it's 16.

In NH4NO3, we have two nitrogens, so multiply 14.01 by 2: 14.01 * 2 = 28.02 g.

There are four hydrogens, so multiply 1.01 by 4: 1.01 * 4 = 4.04 g.

There are three oxygens, so multiply 16 by 3: 16 * 3 = 48 g.

Add these together to get the total mass of this compound: 28.02 + 4.04 + 48 = 80.06 g.

Now find the mass of nitrogen, which we actually already found: 2 * 14.01 = 28.02 g.

Divide 28.02 by 80.06 and multiply by 100:

(28.02 / 80.06) * 100 = 35.00%

Hope this helps!

the answer is the

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