1.20 L of oxygen gas is held in a flexible vessel at STP. If the
vessel is transported to the bottom of Pacific Ocean where the
pressure is 100 atm and the temperature is 15 °C, what is the
new volume of the gas?

The new volume of the gas when the vessel is transported to the bottom of the Pacific Ocean is 0.013 L

From the question given above, the following data were obtained:

Initial volume (V₁) = 1.2 L

Initial pressure (P₁) = STP = 1 atm

Initial temperature (T₁) = STP = 273 K

New pressure (P₂) = 100 atm

New temperature (T₂) = 15 °C = 15 + 273 = 288 K

Using the combined gas equation, the new volume of gas can be obtained as follow:

P₁V₁/T₁ = P₂V₂/T₂

(1 × 1.2) / 273 = (100 × V₂) / 288

1.2 / 273 = (100 × V₂) / 288

Cross multiply

273 × 100 × V₂ = 1.2 × 288

27300 × V₂ = 345.6

Divide both side by 27300

V₂ = 345.6 / 27300

Therefore, the new volume of the gas is 0.013 L

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New Volume = 0.013 Liter

Explanation:

Combined Gas Law Problem

P₁V₁/T₁ = P₂V₂/T₂

P₁ = 1 atm

V₁ = 1.2 Liters

T₁ = 0°C = 273 K

P₂ = 100 atm

V₂ = V₁(P₁/P₂)(T₂/T₁)

T₂ = 15°C = (273 + 15)K =   288K

P₂ = 1.2L(1atm/100atm)(288K/273K) = 0.013 Liter

we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).