Series circuit containing 2 light bulbs, three wires, and a power source. What would happen if one of the light bulbs burnt out? Why would this happen?

The correct answer is no bulb will glow if one burns out because the current flow is disrupted.

Explanation:

We make a series connection of two bulbs with the help of 3 wires and a power source.

One bulb burns out.

Therefore the circuit is now broken and the current cannot flow from one end to the other end of the circuit as because the bulb that burnt out used to help in completing the circuit.

Thus no bulb lights up when current is passed in the connection.

radioactive decay occurs in unstable atomic nuclei – that is, ones that don't have enough binding energy to hold

the nucleus together due to an excess of either protons or neutrons.

im pretty sure its b