How many moles are equal to 3.15x10^23 molecules of ethyne, C2H2?

0.523 moles

Explanation:

(3.15×10²³) / (6.022×10²³)= 0.523 moles

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.

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