2.00 moles of an ideal gas was found to occupy a volume of 17.4 L at a pressure of 3.00 atm and at a temperature of 45 °C. Calculate the value of the gas constant 'R' in (Latm)/(molK)

R = 0.08208 L·atm/mol·K (based on data given)

Explanation:

PV = nRT => R = PV/nT

P = Pressure in atmospheres = 3.00 atm

V = Volume in Liters = 17.4 Liters

n = moles of substance = 2.00 moles

T = temperature in Kelvin = 45°C + 273 = 318K

R = (3.00atm)(17.4L)/(2.00mol)(318K) = 0.08208 L·atm/mol·K

the law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products