Use the data in Appendix B in the textbook to calculate ΔH∘ΔH∘ (in kilojoules) for the reaction. Express your answer using four significant figures. ΔH∘fΔHf∘ = nothing kJkJ SubmitRequest Answer Part B The entropy change for the reaction is ΔS∘ΔS∘ = +36.7J/KJ/K. Is the reaction spontaneous at 25 ∘C∘C? The entropy change for the reaction is = +36.7. Is the reaction spontaneous at 25 ? Yes No

Yes

Explanation:

Positive value of entropy implies increase in disorder which means its a spontaneous process

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.