Use the specific heat capacity that you calculated for granite to determine how many grams of granite at the initial temperature of 80 °C must mix with 3,000 g of water at the initial temperature of 20 °C to result in a final system temperature of 20.45 °X. (Hunt: Start by calculating how much heat energy is needed to change the water’s temperature by 0.45 °C). Show your work. Use the Gizmo to check your answer.

Explanation:

specific heat of granite s = .79 J / g / k

let the mass of granite = m

heat lost by granite = heat gained by water

heat lost = mass x specific heat x drop in temperature

= m x .79 x (80 - 20.45)

heat gained by water

= 3000 x 4.186 x (20.45- 20)

heat lost by granite = heat gained by water

m x .79 x 59.55  =  3000 x 4.186 x .45

m = 120.12 g .

The mass of granite is approximately equal to 120 g.

The specific heat capacity refers to the amount of energy required or needed to raise the temperature of 1 gram of a material or substance by 1° C.

Let assume that:

The heat energy gained by water can be calculated using the formula:

Q = mcΔT

where;

m = mass = 1000 g

c = specific heat = 4.183 J/g° C

ΔT = change in temperature

Q = 1000 g × 4.183 J/g° C × (2.93 - 0)° C

Q =  1000 g × 4.183 J/g° C × (2.93) ° C

Q = 12256.19 J

Q = 12.256 kJ

The next step is to determine the specific heat of granite.

Since;

The heat gained by water = Heat lost by granite.

The heat lost by granite = 12.256 kJ

Using the relation;

Q = mcΔT

Making (c) the subject of the formula:

The specific heat of granite = 0.795 J/g° C

Recall from the given parameters;

∴

Again, heat gained by water = heat lost by granite

To determine the mass of granite, make the subject of the formula;

i.e.

Therefore, we can conclude that the mass of granite is approximately equal to 120 g.

Learn more about specific heat capacity here:

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under a microscope, cancer cells may look very different from normal cells. they often have different sizes and some may be larger than normal while others are smaller. cancer cells are often abnormally shaped and the control centre of the cell (the nucleus) may have an abnormal appearance.

i think? ?

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.