Sodium chloride, NaCl forms in this reaction between sodium and chlorine. 2Na(s) + Cl2(g) → 2NaCl(s) How many moles of NaCl result from the complete reaction of 3.9 mol of Cl2? Assume that there is more than enough Na.

7.8 moles of NaCl result from the complete reaction of 3.9 mol of

Explanation:

To calculate the moles :

As is the excess reagent, is the limiting reagent as it limits the formation of product.

According to stoichiometry :

1 mole of gives = 2 moles of

Thus 3.9 moles of will give=  of

7.8 moles of NaCl result from the complete reaction of 3.9 mol of

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