What steps would you take in a lab to prepare 1000 mL of a 2 M NaCl solution

The answer to your question is below

Explanation:

Data

Volume = 1000 ml

Concentration = 2M

molecule = NaCl

Process

1.- Calculate the number of moles of NaCl

Molarity = moles/Volume

-Solve for volume

moles = Molarity x Volume (liters)

-Substitution

moles = 2 x 1

-Result

moles = 2

2.- Determine the molar mass of NaCl

NaCl = 23 + 35.5 = 58.5 g

3.- Calculate the mass of NaCl to prepare the solution

               58.5 g  1mol

                   x        2 moles

                       x = (2 x 58.5) / 1

                       x = 117g

4.- Weight 117 g of NaCl, place them in a volumetric flask (1 l), and add enough water to prepare the solution.

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the ratio of the conjugate base to the acid required to attain the desired ph.