A sample of a gas occupies 1.80 L at -10. °C and 450. Torr. What will be the temperature if the pressure is increased to 800. Torr and the volume is decreased by 1/3?

156 K

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas = 450 torr

= final pressure of gas = 800 torr

= initial volume of gas = 1.80 L

= final volume of gas =

= initial temperature of gas =

= final temperature of gas = ?

Now put all the given values in the above equation, we get:

Thus the final temperature will be 156 K

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