Calculate the mass of solid CuSO4∙5H2O (±0.1 g) needed to prepare 25.00 mL of 0.10 M Cu2+ solution. When calculating the molar mass, include the full formula of the CuSO4∙5H2O (s) – its formula is called "copper (II) sulfate pentahydrate" and includes five water molecules.

The mass of solid CuSO4∙5H2O is 0.624 grams

Explanation:

Step 1: Data given

Volume of Cu^2+ = 25.00 mL = 0.025L

Molarity of Cu^2+ = 0.10 M

Molar mass of CuSO4 *5H2O = 249.68 g/mol

Step 2: Calculate moles Cu^2+

Moles Cu^2+ = molarity Cu^2+ * volume Cu^2+

Moles Cu^2+ = 0.10 M * 0.025 L

Moles Cu^2+ = 0.0025 moles

Step 3: Calculate moles CuSO4 *5H2O needed

For 1 mol CuSO4 *5H2O we have 1 mol Cu^2+

For 0.0025 moles Cu^2+ we'll have 0.0025 moles CuSO4 *5H2O

Step 4: Calculate mass CuSO4 *5H2O

Mass CuSO4 *5H2O = moles / molar mass

Mass CuSO4 *5H2O = 0.0025 moles / 249.68 g/mol

Mass CuSO4 *5H2O = 0.624 grams

The mass of solid CuSO4∙5H2O is 0.624 grams

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i