If the solubility of a gas is 10.5 g/L at 650 kPa pressure, what is the solubility of the gas when the pressure is 200 kPa? Show your work.

3.23 g/L

Explanation:  

P1= 650 kPa

P2= 200 kPa

S1= 10.5 g/L

S2= ?    

S2 = P2 x S1/P1  

S2 = ( 200 kPa x 10.5 g/L)/(650 kPa)

S2 = 3.23 and since we are looking for the solubility of the gas when the pressure is 200 kPa, so we use g/L, 3.23 g/L.

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h let me think

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.