Ammonia, NH3 (Delta. Hf = –46.2 kJ), reacts with oxygen to produce water (Delta. Hf = –241.8 kJ) and nitric oxide, NO (Delta. Hf = 91.3 kJ), in the following reaction: 4 upper N upper H subscript 3 (g) plus 5 upper O subscript 2 (g) right arrow 6 upper H subscript 2 upper O (g) plus 4 upper N upper O (g). What is the enthalpy change for this reaction? Use Delta H r x n equals the sum of delta H f of all the products minus the sum of delta H f of all the reactants.

The enthalpy of reaction is -900.8 kJ

Explanation:

The chemical equation is as follows:

The equation for the enthalpy change of the above reaction is:

We are given:

Putting values in above equation, we get:

The enthalpy of reaction is -900.8 kJ

what are the statements?

explanation:

give me the statements and i'll tell you which is correct

hey there!

boiling point is the temperature at which the vapor pressure of the liquid equals atmospheric pressure. the vapor pressure of solvent molecules is decreased when a solute is added, so a higher temperature is required to increase the number of solvent molecules in the gas phase above the liquid.

at the freezing point, the vapor pressures of the solid and liquid are equal; a lower temperature is needed to reduce the number of solvent particles above the liquid.

hope this you

tobey