Calculate the standard entropy of reaction for solid sodium reacting with chlorine gas to form solid NaClNaCl at 25 ∘C∘C. 2Na(s)+Cl2(g)→2NaCl(s)2Na(s)+Cl2(g) →2NaCl(s) Substance and State S∘[J/(K⋅mol)]S∘[J/(K⋅mol)] Na(s)Na(s) 51.2 Cl2(g)Cl2(g) 223.0 NaCl(s)NaCl(s) 72.1

1. they vary with a higher number because boiling is way hotter than melting

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.