Chemistry, 24.04.2020 00:41 pineappledogpie1608
Given the equation representing a reversible reaction:
CH3COOH(aq) + H2O <—> CH3COO-(aq) + H3O+(aq)
according to one acid-base theory, the two H+ donors in the equation are
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Answer asap need by wednesday morning explain how a buffer works, using an ethanoic acid/sodium ethanoate system including how the system resists changes in ph upon addition of a small amount of base and upon addition of a small amount of acid respectively. include the following calculations in your i. calculate the ph of a solution made by mixing 25cm3 0.1m ch3cooh and 40cm3 0.1m ch3coo-na+. [ka = 1.74 x 10-5 m] ii. calculate the ph following the addition of a 10cm3 portion of 0.08 m naoh to 500cm3 of this buffer solution. iii. calculate the ph following the addition of a 10cm3 portion of 0.08 m hcl to 200cm3 of the original buffer solution.
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Given the equation representing a reversible reaction:
CH3COOH(aq) + H2O <—> CH3COO-(aq...
CH3COOH(aq) + H2O <—> CH3COO-(aq...
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