How much energy is needed to heat 20.0 grams of water from 25.0°C to 50.0 °C?

The answer to your question is Q = 2093 J

Explanation:

Data

Energy = Q = ?

mass = 20 g

Temperature 1 = 25°C

Temperature 2 = 50°C

Specific heat = Cp = 4.186 J/g°C

Formula

Energy = Q = mCp(Temperature 2 - Temperature 1)

Substitution

               Q = (20)(4.186)(50 - 25)

Simplification

               Q = (20)(4.186)(25)

Result

              Q = 2093 J

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

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