23 ml of oxygen collected over water and has a pressure of 636 mmhg at 23 c. what is the pressure of the dry gas at stp

Answer : The pressure of the dry gas at stp is, 0.602 mmHg

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas = 636 mmHg

= final pressure of gas = ?

= initial volume of gas = 23 mL = 0.023 L

= final volume of gas at STP = 22.4 L

= initial temperature of gas =

= final temperature of gas at STP =

Now put all the given values in the above equation, we get:

Therefore, the pressure of the dry gas at stp is, 0.602 mmHg

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be