Chemistry, 23.04.2020 02:06 reynellemt

Sarah lives beside the ocean in Eureka, California. Her penpal, Ruby, lives in Redding, California, which is located inland. As a school project one year, Sarah and Ruby decide to collect local climate data and compare the average monthly high and low temperatures from their cities. The data they collect are shown below. Month Eureka Average High Eureka Average Low Redding Average High Redding Average Low January 54°F 41°F 55°F 35°F February 55°F 43°F 58°F 38°F March 55°F 43°F 70°F 41°F April 56°F 45°F 71°F 45°F May 58°F 48°F 80°F 52°F June 60°F 51°F 89°F 60°F July 61°F 52°F 98°F 64°F August 62°F 53°F 97°F 61°F September 63°F 51°F 89°F 56°F October 61°F 49°F 69°F 45°F November 58°F 45°F 60°F 40°F December 55°F 42°F 55°F 34°F Based on the climate data that Sarah and Ruby collect, they can conclude that

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Answer from: Pooh1189

Temperature variance at Redding > > Temperature variance beside at Eureka

Monthly temperatures at Redding are generally higher than the monthly temperatures beside the ocean at Eureka

Explanation:

Month January

Eureka Eureka Redding Redding

Average Average Average Average

High Low High Low

54°F 41°F 55°F 35°F

February

55°F 43°F 58°F 38°F

March

55°F 43°F 70°F 41°F

April

56°F 45°F 71°F 45°F

May

58°F 48°F 80°F 52°F

June

60°F 51°F 89°F 60°F

July

61°F 52°F 98°F 64°F

August

62°F 53°F 97°F 61°F

September

63°F 51°F 89°F 56°F

October

61°F 49°F 69°F 45°F

November

58°F 45°F 60°F 40°F

December

55°F 42°F 55°F 34°F

58 46.92 74.25 47.58 Mean

3.16 4.25 15.99 10.63 Standard Dev

9.97 14.08 255.84 112.992 Variance

63 53 98 64 Max

54 41 55 34 Min

Based on the climate data that Sarah and Ruby collect, they can conclude that

From the data we have

From the data it is observed that the temperatures beside the ocean in Eureka are lesser than and more stable (vary less) than the temperatures in Redding, also the temperatures in Redding are much higher than the temperatures beside the ocean in Eureka.

Answer from: Quest

remember that hf is only the energy of one photon. not two. not three. one. 1) 5.12 * 10^3 photons find the energy of one photon, then determine how many photons are needed to reach the sensitivity. e = hf = (6.626 * 10^-34 js)(5.95 * 10^19 hz) = 3.94247 * 10^-14 j per photon (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons round to three sig figs. 2) 5.77 * 10^-17 j energy of pulse = energy per photon * number of photons = hfn = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250) = 5.774559 * 10^-17 j round to three sig figs. 3) 4.07 * 10^8 kj/mol 10^12 pm = 1 m c = fλ f = c/λ e = hf = hc/λ = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol) = 40702571.4 kj/mol round to three sig figs. 4) 9.94 * 10^-1 m e = hc/λ λ = hc / e = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j) = 0.9939 m round to three sig figs. 5) 9.06 * 10^3 photons energy of pulse = energy per photon * number of photons number of photons = energy of pulse / energy per photon = energy of pulse / (hf) = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)] = 9055.23695 photons round to three sig figs. 6) 2.78 * 10^-15 j this is problem 1, except in reverse. sensitivity = minumum number of photons * energy per photon = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz) = 2.78070758 × 10^-15 j round to three sig figs.

Answer from: Quest

Answer two atoms of oxygen;