A reaction between liquid reactants takes place at -8.0 C in a sealed, evacuated vessel with a measured volume of 10.0 L. Measurements show that the reaction produced 12 g or carbon dioxide gas. Calculate the pressure of carbon dioxide in the reaction vessel after the reaction. You may ignore the volume of the liquid reactants. Round you answer to 2 significant digits.

Answer : The pressure of carbon dioxide in the reaction vessel after the reaction is, 0.59 atm.

Explanation : Given,

Mass of = 12 g

Molar mass of = 44 g/mol

First we have to calculate the moles of carbon dioxide gas.

Now we have to calculate the pressure of carbon dioxide gas.

Using ideal gas equation:

where,

P = pressure of gas = ?

V = volume of gas = 10.0 L

n = number moles of gas = 0.273 mol

R = gas constant = 0.0821 L.atm/mol.K

T = temperature of gas =

Now put all the given values in the above formula, we get:

Therefore, the pressure of carbon dioxide in the reaction vessel after the reaction is, 0.59 atm.

pla·gia·rism

/ˈplājəˌrizəm/

learn to pronounce

noun

the practice of taking someone else's work or ideas and passing them off as one's own.

explanation:

he uptake of drugs from the intestine is often strongly influenced by diffusion. for example, consider a water-insoluble steroid for treating inflammation that is solubilized in aggregates of detergent molecules, called micelles. these micelles, aggregates of 80 soap molecules, have a molecular weight of 24,000, a diameter of 2.6 nm, and a charge of -27. the positively charge ions (counterions) in this system are na".