A saturated solution of KClO3 is dissolved in 100 mL of water. If the saturated solution is cooled from 90oC to 60oC, how many grams of precipitate will be formed?

24 g

Explanation:

To find the mass of precipitate that will be formed we need to use the solubility curve of KClO₃ in the water. From that graphic of solubility curve of KClO₃ in water, we have that:  

The mass of the saturated solution of KClO₃ in 100 mL of water at 90 °C is = 50 g

The mass of the saturated solution of KClO₃ in 100 mL of water at 60 °C is = 26 g

Hence, by the difference of the mass of KClO₃ between 90 °C and 60 °C we can find the grams of precipitate that will be formed:

Therefore, 24 g of KClO₃ precipitate will be formed.

I hope it helps you!  

- decrease the number of plants and animals living in the water.

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