The copper(I) ion forms a chloride salt (CuCl) that has Ksp = 1.2 x 10-6. Copper(I) also forms a complex ion with Cl-:Cu+ (aq) + 2Cl- (aq) ⇄ CuCl2- (aq) K = 8.7 x 104(a) Calculate the solubility of CuCl in pure water. (Ignore CuCl2- formation for part a).(b) Calculate the solubility of CuCl in 0.100 M NaCl solution.

(a) The solubility of CuCl in pure water is .

(b) The solubility of CuCl in 0.1 M NaCl is .

Explanation:

(a)  Chemical equation for the given reaction in pure water is as follows.

Initial:                         0            0

Change:                    +x           +x

Equilibm:                   x             x

And, equilibrium expression is as follows.

             x =

Hence, the solubility of CuCl in pure water is .

(b)  When NaCl is 0.1 M,

       ,  

   ,  

Net equation:

                          = 0.1044

So for,

Initial:                     0.1                 0

Change:                -x                   +x

Equilibm:            0.1 - x                x

Now, the equilibrium expression is as follows.

              K' =

         0.1044 =

              x =

Therefore, the solubility of CuCl in 0.1 M NaCl is .

a is the answer to this question

explanation: