Arrange these 3 reactions according to increasing DS. (1) CH4(g) H2O(g) --> CO(g) 3 H2(g) (2) C(s) O2(g) --> CO2(g) (3) H2O2(l) --> H2O(l) 1/2 O2(g) 1 < 3 < 2 2 < 3 < 1 2 < 1 < 3 3 < 2 < 1 3 < 1 < 2

1 < 3 < 2.

Explanation:

Entropy is the measurement of the degree of disorderliness in a system. The term ''entropy" is one of the important aspect in kinetics and thermodynamics. Entropy is designated with the alphabet symbol "S" and a change in entropy is ∆S.

The main idea in order to solve this question is very simple. Let us make reference to your clothes that you wear. At first, your clothes when you wear them, they are neat and clean but as time goes by the clothes will get dirty, this is a layman example of entropy.

Okay, let me explain further if you look at the first reaction you will notice that we have 2 moles in the reactant sides and 4 moles in the products sides, which means that the entropy has increased.

CH4(g) + H2O(g) --> CO(g) + 3 H2(g).

For the second equation, the entropy is increasing because the the solid reactant produces a gaseous product.

But in this reaction the number of moles of the products has decreased.

C(s) + O2(g) --> CO2(g)

For the third Equation, the the state changes from liquid to gas.

H2O2(l) --> H2O(l) + 1/2 O2(g)

Note that the entropy increases from solid to liquid to gas. That is, gas has the highest degree of entropy and solid has the lowest degree of entropy.

Look at reaction (1) gas to gas.

Look at Reaction (2) solid to gas( great improvement/Increament).

Look at Reaction (3) liquid to gas( increases).

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2