At a certain temperature, iron (II) oxide, FeO, can react with carbon monoxide, CO, to form elemental iron, Fe, and carbon dioxide, CO2. The value of Kp at that temperature is 0.242. What is the pressure of CO2 at equilibrium if a sample of FeO was initially in a container with CO at a pressure of 0.95 atm? The chemical reaction involved in this process is: FeO(s) + CO(g) ⟷ Fe(s) + CO2(

The pressure of CO2 at the equilibriumis 0.185 atm

Explanation:

Step 1: Data given

The value of Kp at that temperature is 0.242

FeO was initially in a container with CO at a pressure of 0.95 atm

Step 2: The balanceequation

FeO(s) + CO(g) ⟷ Fe(s) + CO2(g)

Step 3:The initial pressure

pCO = 0.95 atm

pCO2 = 0 atm

Step 4: The pressure at the equilibrium

pCO = 0.95 - x atm

pCO2 = X atm

Step 5: Calculate Kp

Kp = pCO2 / pCO

0.242 = X / (0.95 - X)

X = 0.185

pCO = 0.95 - 0.185 =  0.765 atm

pCO2 = 0.185 atm

The pressure of CO2 at the equilibriumis 0.185 atm

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.