What is the empirical formula for a compound that is 43.4% C, 1.2% H, 38.6% O, and 16.9% N?

C3HO2N

Explanation:

C: 43.4 g x 1 mole= 3.613444679 / 1.190547056 = 3.0412.0107 g

H: 1.2 g x 1 mole= 1.190547056 / 1.190547056 = 1.00794

O : 38.6 g x 1 mole= 2.412590472 / 1.190547056 = 2.0315.9994 g

N : 16.9 g x 1 mole= 1.206561984 / 1.190547056 = 1.0114.00674 g

C=3

H=1

O=2

N=1

: C3HO2N

the correct answer is boyle

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.