Approximately how many ice cubes must melt to cool 650 milliliters of water from 29°C to 0°C? Assume that each ice cube contains 1 mole of H2O and is initially at 0°C. ∆H(fusion) = 6.02 kJ/mol; ∆H(vaporization) = 40.7 kJ/mol c(solid) = 2.09 J/g°C; c(liquid) = 4.18 J/g°C; c(gas) = 1.97 J/g°C Enter your answer numerically.

Answer : The number of ice cubes melt must be, 13

Explanation :

First we have to calculate the mass of water.

Density of water = 1.00 g/mL

Volume of water = 650 mL

Now we have to calculate the heat released on cooling.

Heat released on cooling =

where,

m = mass of water = 650 g

c = specific heat capacity of water =

= final temperature =

= initial temperature =

Now put all the given values in the above expression, we get:

Heat released on cooling =

Heat released on cooling = 78793 J = 78.793 kJ   (1 J = 0.001 kJ)

As, 1 ice cube contains 1 mole of water.

The heat required for 1 ice cube to melt = 6.02 kJ

Now we have to calculate the number of ice cubes melted.

Number of ice cubes melted =

Number of ice cubes melted =

Number of ice cubes melted = 13.1 ≈ 13

Therefore, the number of ice cubes melt must be, 13

bcde is the incorrect answer it is a

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2