In cases of ethylene glycol poisoning, treatment involves administration of Ethanol (grain alcohol), which works by competitively inhibiting ADH, an enzyme that oxidizes ethylene glycol to organic acids. As a competitive inhibitor, ethanol: decreases apparent Km without affecting Vmax· increases apparent Vmax without affecting Km. decreases both apparent Vmax and apparent Km. increases apparent Km without affecting Vmax· decreases apparent Vmax without affecting Km.

Option B is the correct option- Ethanol increases apparent Km without affecting Vmax.

Explanation:

Vmax remains the same, and Km increases in competitive inhibition. There is an increment in Km because competitive inhibitors interfere with substrate binding to the enzyme. Vmax is not affected because the competitive inhibitor cannot bind to ES and therefore does not alter the catalysis.

Option B is the correct option- Ethanol increases apparent Km without affecting Vmax.

In the attached image, the first picture is the Michaelis Menten Plot for competitive inhibition in which an increase in km but constant Vmax is observed.

In the images,  ............................. represents the case with competitive inhibitor, while _______________ represents the case without competitive inhibitor.

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol