Explain how you would determine the number of grams of Cu(NO3)2 that would be needed to make 1052 mL of a 2.50 M solution of Cu(NO3)2

The answer to your question is 493.31 grams

Explanation:

Data

mass of Cu(NO₃)₂ = ?

volume = 1052 ml

concentration = 2.50 M

Process

1.- Write the formula to determine the Molarity

Molarity = moles/volume

-Solve for moles

moles = Molarity x volume

-Substitution

moles = 2.50 x 1.052

-Result

moles = 2.63

2.- Calculate the molar mass of Cu(NO₃)₂

Cu(NO₃)₂ = (63.55 x 1) + (14.01 x 2) + (16 x 6)

               = 63.55 + 28.02 + 96

               = 187.57 g

3.- Calculate the grams of Copper nitrate

                   187.57 g 1 mol

                     x           2.63 moles

                              x = (2.63 x 187.57) / 1

                              x = 493.31 / 1 grams

                              x = 493.31 grams

your answer is a. the enthalpy of formation for a pure element in its standard state is always positive.

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