Carbon disulfide burns in oxygen to yield carbon dioxide and sulfur dioxide according to the chemical equation cs2(ℓ) + 3 o2(g) −→ co2(g) + 2 so2(g). if 1.25 mol of cs2 is combined with 0.57 mol of o2, identify the limiting reactant.

oxygen is the limiting reagent

Explanation:

cs2(ℓ) + 3 o2(g) −→ co2(g) + 2 so2(g)

from the balanced equation

1 mole carbon disulfide requires 3 mole of oxygen

1.25 moles of cs₂ will required 3.75 mole of oxygen

while 0.57 mole of oxygen will require 0.19 mole of cs₂

comparing, oxygen is the limiting reagent since 0.57 mole of oxygen will require just 0.19 mole out of 1.25 mole meaning cs₂ is in excess.

i think it's c. if you look search electronic symbol on google and then click on wiki it shows you a