If you have 40 grams of potassium nitrate in 100 grams of water at 20 C:

a. How many grams of potassium nitrate will dissolve?

b. How many grams of potassium nitrate will fall to the bottom of the container?

c. At this temperature, 20 C, is this solution saturated, unsaturated or

supersaturated? EXPLAIN.

d. At what temperature will the amount of potassium nitrate that fell to the bottom will also dissolve?

e. If this solution was heated to 90 C, would the solution be saturated, unsaturated or supersaturated? EXPLAIN.

Explanation:The final homogenous solution, after cooling it to 40°C, will contain 47 g of potassium sulfate disolved in 150 g of water, so you can calculate the amount disolved per 100 g of water in this way:

[47 g of solute / 150 g of water] * 100 g of g of water = 31.33 grams of solute in 100 g of water.

So, when you compare with the solutiblity, 15 g of solute / 100 g of water, you realize that the solution has more solute dissolved with means that it is supersaturated.

To make a saturated solution, 15 grams of potassium sulfate would dissolve in 100 g of water.

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a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.