For the reaction 2NH3(g) + 2O2(g)N2O(g) + 3H2O(l) H° = -683.1 kJ and S° = -365.6 J/K The standard free energy change for the reaction of 1.57 moles of NH3(g) at 273 K, 1 atm would be kJ. This reaction is (reactant, product) favored under standard conditions at 273 K. Assume that H° and S° are independent of temperature.

= -457.9 kJ and reaction is product favored.

Explanation:

The given reaction is associated with 2 moles of

Standard free energy change of the reaction () is given as:

              , where T represents temperature in kelvin scale

So,

So, for the reaction of 1.57 moles of ,

As, is negative therefore reaction is product favored under standard condition.