A 0.5781 g sample of a pure soluble bromide compound is dissolved in water, and all of the bromide ion is precipitated as AgBr by the addition of an excess of silver nitrate. The mass of the resulting AgBr is found to be 1.1166 g. What is the mass percentage of bromine in the original compound? %

82.18% is the mass percentage of bromine in the original compound.

Explanation:

Mass of AgBr = 1.1166 g

Moles of AgBr =

According to reaction, 1 mole of AgBr is obtained from 1 mole of bromide ions , then 0.0059466 moles of AgBr will be formed from :

of bromide ions

Mass of 0.005939 moles of bromide ions :

0.0059466 mol × 79.90 g/mol = 0.4751 g

Mass of the sample = 0.5781 g

Mass percentage of bromine in sample :

82.18% is the mass percentage of bromine in the original compound.

a

explanation:

a rain shadow is a dry region of land on the side that is protected against the prevailing winds of a mountain range. the prevailing winds are the winds that occur most of the time in a particular place of the earth

prevailing winds carry air toward the mountain range. as the air rises up over a mountain range, the air cools, water vapor condenses, and clouds form. on this side of the mountains, called the windward side, precipitation falls in the form of  rain  or snow. this dry air produces a  rain shadow.