Calculate the pH of a 0.05 M solution of NaOH.

The pH is about 12.7.

Explanation:

NaOH is a strong base, meaning it will dissociate basically completely in solution to form  

N

a

+

and  

O

H

−

ions in solution.

One mole of  

O

H

−

ions is created for every mole of NaOH that is dissolved. If it's a .05 M solution of NaOH, then it can also be interpreted to be a .05M solution of  

O

H

−

.

p

O

H

(The pH scale for bases) can be found by taking the negative logarithm of  

O

H

−

concentration.

p

O

H

=  

−

log

[

.05

M

]

= 1.3.

However, we are trying to find  

p

H

, so we must use the formula

p

O

H

+

p

H

=

14

.

Now that we know  

p

O

H

=

1.3

,

p

H

=

14

−

1.3

=

12.7

.

(found the answer here https://socratic.org/questions/what-is-the-ph-of-a-0-050-m-naoh-solution)

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

the product of the pressure and volume is also constant