Calculate the Kelvin temperature to which 10.0 L of a gas at 27 °C would have to be heated to change the volume to 12.0 L. Units of Kelvin are assumed here for the answer you enter so just put the number value.

According to the question,

Volume,

Temperature,

By using the relation, we get

→

then,

→  

→  

By substituting the values,

Thus the above answer is correct.

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360.18 K is the Kelvin temperature to which 10.0 L of a gas at 27 °C would have to be heated to change the volume to 12.0 L.

Explanation:

Data given:

Initial volume of the gas, V1 = 10 litres

Initial temperature of the gas, T1 = 27° C or 273.15+27 = 300.15 K

Final volume of the gas obtained, V2 = 12 Litres

final temperature to obtain the above volume, T2 =?

temperature value in Kelvin

Applying Charles' Law to the data given,

rearranging the equation to get T2,

T2 =

Putting the values in the equation:

T2 =

T2 = 360.18 K

The gas will be heated at the temperature of 360.18 K to get its volume changed to 12 litres.

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