How many moles of CaCl2 will be produced from 1.4 moles of HCl reacting with calcium hydroxide?

0.7 mol of CaCl2 is produced.

Explanation:

First, you have to create a balanced equation :

Ca(OH)2 + 2HCl -> CaCl2 + 2H2O

Next, we have to find the ratio using the coefficients of the equation :

1Ca(OH)2 + 2HCl -> 1CaCl2 + 2H20

Ratio,

1 : 2 : 1 : 2

By looking at the ratio, we know that 2 ratio of HCl react to produce 1 ratio of CaCl2. Now, we can find the mole of CaCl2 :

ratio of 2 = 1.4 mol

ratio of 1 = 0.7 mol

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

the ratio of the conjugate base to the acid required to attain the desired ph.