The total pressure in a 1.00 liter container is 725 mm Hg. The container contains water vapor and nitrogen gas. If the partial pressure of the water vapor is 225 mm Hg, what is the partial pressure of the nitrogen gas.

Explanation:PRESSURE: atmospheres or mm Hg; 1 atm = 760 mm Hg

TEMPERATURE: Kelvin, K, which is o

C + 273

STP: Standard Temperature and Pressure: 273 K and 1 atm (or 760 mm Hg)

BOYLE'S LAW (temperature is constant): PV = constant

This is an inverse relationship: if one variable increases the other must

decrease.

CHARLES' LAW (pressure is constant): V = constant x T

This is a direct relationship: if one variable increases so does the other.

GAY-LUSSAC'S LAW (volume is constant): P = constant x T

This is a direct relationship: if one variable increases so does the other.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

plasma is the state of matter where the substance is ionized and has no definite shape or volume. the fact of being ionized makes the substance a good electrical conductor.