Chemistry, 18.04.2020 04:09 kaybug27

A sample of a gas is contained in a closed rigid cylinder. According to the kinetic molecular theory, what occurs when the gas inside the cylinder is heated?

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When heating, the temperature is increased, therefore, the average kinetic energy is increased so the molecules will start moving more rapidly.

Explanation:

Hello,

Kinetic molecular theory is based on a series of specific statements:

- Gases are constituted by a raft of particles that are considered as both hard and spherical bodies under a state of constant and random movement.

- The particles are constantly moving in a straight line until they collide to each other or against walls of the container.

- There is no force of attraction nor repulsion among gas particles or among the particles and the walls of the container.

- Collisions are said to be perfectly elastic.

- The average kinetic energy of a raft of gas particles is temperature-dependent only.

- The higher the temperature the higher the average kinetic energy of the gas and the other way around.

In such a way, considering the last two statements, when heating, the temperature is increased, therefore, the average kinetic energy is increased so the molecules will start moving more rapidly in comparison to the initial state.

Best regards.

Answer from: Quest

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction: so₂cl₂ (g) = so₂ (g) + cl₂ (g) total

the moles at equilibrium: 1 - α α α = 1+α

concentrations: 1 - α α α = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

$k_{c}$ = $\frac{[so2cl2] x [cl2]}{[so2cl2]}$

or, $\frac{\alpha ^{2} }{(1-\alpha)v }$

or, $k_{c}$ = $\frac{\alpha ^{2} }{(1-\alpha) }$ (at v = 1l)

the reaction: so₂cl₂ (g) = so₂ (g) + cl₂ (g) total

the moles at equilibrium: 1 - α α α = 1+α

concentrations: (1 - α)/0.5 α/0.5 α/0.5 = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

$\frac{[so2cl2] x [cl2]}{[so2cl2]}$

or, $\frac{\alpha ^{2} }{(1-\alpha)0.5 }$

$\frac{\alpha ^{2} }{(1-\alpha) }$ = $\frac{\alpha ^{2} }{(1-\alpha) 0.5}$

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%

Answer from: Quest

Sorry i dont understand the question can you rephase it?

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A sample of a gas is contained in a closed rigid cylinder. According to the kinetic molecular theory...

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