Sodium hydrogen carbonate (NaHCO3) , also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Acid indigestion is the burning sensation you get in your stomach when it contains too much hydrochloric acid (HC1) , which the stomach secretes to help digest food. Drinking a glass of water containing dissolved NaHCO3 neutralizes excess HC1 through this reaction:

HC1(aq) + NaHCO3 (aq) → NaC1 (aq) + H2O (I) + CO2 (g)

The CO2 gas produced is what makes you burp after drinking the solution.

Suppose the fluid in the stomach of a man suffering from indigestion can be considered to be 50. mL of a 0.034 M HC1 solution. What mass of NaHCO 3 would he need to ingest to neutralize this much HC1 ?
Be sure your answer has the correct number of significant digits.

Mass of NaHCO₃ required for the neutralization = 0.143 g

Explanation:

The reaction between HCl and NaHCO₃ is given as

HCl + NaHCO₃ → NaCl + H₂O + CO₂

The fluid in the stomach of a man suffering from indigestion is considered to be 50 mL of a 0.034 M HCl solution. The mass of NaHCO₃ he would need to ingest to neutralize this much HCl.

We forst need to calculate the number of moles of HCl in 50.0 mL of 0.034 M HCl

(Number of moles) = (Conc in mol/L) × (Volume in L)

Conc in mol/L = 0.034 M

Volume in L = (50/1000) = 0.05 L

Number of moles of HCl = 0.034 × 0.05 = 0.0017 moles

From the stoichiometric balance of the reaction,

1 mole of HCl requires 1 mole of NaHCO₃

0.0017 moles of HCl will require 0.0017 moles of NaHCO₃.

So, we can then.calculate the mass of NaHCO₃ required for this neutralization.

Mass = (Number of moles) × (Molar mass)

Molar mass of NaHCO₃ = 84.007 g/mol

Mass of NaHCO₃ required for this neutralization = 0.0017 × 84.007 = 0.1428119 g = 0.143 g to 3 s.f because calculated values usually have 1 more significant figure than the given parameters for the calculations.

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