A student performed a similar experiment with four hypothetical cations, A+, B+, C+, and D+ and two hypothetical anions, X- and Y-. Her data is below:

Analyte X- Y-
A+ yellow ppt yellow ppt
B+ white ppt clear, colorless solution, NR
C+ clear, colorless solution, NR clear, colorless solution, NR
D+ white ppt blue ppt
The student was then provided with an unknown containing one of the anions above. She reacted it with the four hypothetical cations, A+, B+, C+, and D+, her results are below:

Analyte unknown
D+ white ppt
Which of the following statements is most true with regard to this data?

Group of answer choices

a. The unknown anion is most likely X-
b. More tests would need to be performed to identify the anion in the unknown.
c. The unknown anion is most likely Y-

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explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.