Calculate the specific heat capacity of a piece of ice if 1.30 kg of the wood absorbs 6.75×104 joules of heat, and its temperature changes from 32 ºC to 57 ºC.

2076.9 J/kg°C

Explanation:

The equation needed here is:

, where q is the energy in Joules, m is the mass in kg, C is the heat capacity, T_f is the final temperature, and T_i is the initial temperature.

Here, we have q = 6.75* J, m = 1.30kg, T_f = 57, and T_i = 32. So:

Solving for C, we get:

C = 2076.9 J/kg°C

Hope this helps!